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OpenStudy (anonymous):
Please help me with these three problems: 1) a^2-6ab+ab^2 2) -6x^6+30x^5-18x^4 3) -2x^2y^2z^2-8x^4yz^3+6x^3y^2z^3.
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OpenStudy (anonymous):
There are 3 of them. #1 is: a^2-6ab+ab^2
#2 is: -6x^6+30x^5-18x^4
#3 is: -2x^2y^2z^2-8x^4yz^3+6x^3y^2z^3.
OpenStudy (lalaly):
u are asked to factorise or what?
OpenStudy (anonymous):
#1 Factor the expression into a product of binomials
OpenStudy (anonymous):
#2 Factor the greatest common factor
#3 Factor the greatest common factor
OpenStudy (kropot72):
#3 factorises as follows:
2x^2yz^2(-y - 4x^2z + 3xyz)
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OpenStudy (kropot72):
#2 facorises as follows:
6x^4(-x^2 + 5x -3)
OpenStudy (anonymous):
Thank you very much.
OpenStudy (kropot72):
fthrogers, please check the details of question #1. As stated it does not factorise
OpenStudy (anonymous):
It says to factor the expression a^2-6ab+ab^2 into products of binomials.
OpenStudy (kropot72):
Is this what it says?
\[a ^{2}-6ab+ab ^{2}\]
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Is it able to be factored into a product of binomials?
OpenStudy (kropot72):
It can be factorised as follows:
a(a - b(6 - b))
OpenStudy (anonymous):
Thank you so very much.
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