Question

Anyone could HELP me with this please....
How to find the volume of the solid S from: a right circular cone with height h and base radius r

Answer 1

What I try is.. as it was found that
\[r = \sqrt{c ^{2}-h ^{2}}\]
so the cross sectional area is A(h)= pi r^2 = pi (c^2-h^2)
from the drawing..
a=0, b=h so the volume is
\[\int\limits_{0}^{h}A(h) dh = \int\limits_{0}^{h} pi*(c ^{2}-h ^{2}) dh = 1/3 pi * r ^{2} h\]

but this wasn't quite right.

Answer 2

\[\[\int\limits\limits_{0}^{h}A(h) dh = \int\limits\limits_{0}^{h} pi*(c ^{2}-h ^{2}) dh = 1/3 pi * r ^{2} h\]\]

Answer 3

i have learned a formula as 1/3 pi r^2 h.... and i was able to solve problems with this.

Answer 4

@reeba @Rohangrr thanks everyone ;)