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Mathematics 8 Online
OpenStudy (anonymous):

darivatin of quadratic equation

OpenStudy (anonymous):

The derivative of the quadratic equation ax^2 +bx +c is 2ax + b

OpenStudy (anonymous):

how quadratic equation is derived?

OpenStudy (anonymous):

complete the square

OpenStudy (anonymous):

\[ax^2 + bx+c = 0\]\[x^2 + \frac{b}{a}x+\frac{c}{a}\]\[ (x + \frac{b}{2a})^2+\frac{c}{a} - \frac{b^2}{4a^2} = 0\]

OpenStudy (anonymous):

\[ (x + \frac{b}{2a})^2 = - \frac{c}{a} +\frac{b^2}{4a^2} \]

OpenStudy (anonymous):

can you finish?

OpenStudy (anonymous):

yes...but an other question

OpenStudy (anonymous):

that why we break the middle term when solving by the completing square form?

OpenStudy (anonymous):

its because when we expand: \[(x+k)^2 = x^2 + 2kx + k^2\] we have to split the middle term to get the squared form

OpenStudy (anonymous):

thank you......eigenschmeigen....

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