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darivatin of quadratic equation
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The derivative of the quadratic equation ax^2 +bx +c is 2ax + b
how quadratic equation is derived?
complete the square
\[ax^2 + bx+c = 0\]\[x^2 + \frac{b}{a}x+\frac{c}{a}\]\[ (x + \frac{b}{2a})^2+\frac{c}{a} - \frac{b^2}{4a^2} = 0\]
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\[ (x + \frac{b}{2a})^2 = - \frac{c}{a} +\frac{b^2}{4a^2} \]
can you finish?
yes...but an other question
that why we break the middle term when solving by the completing square form?
its because when we expand: \[(x+k)^2 = x^2 + 2kx + k^2\] we have to split the middle term to get the squared form
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thank you......eigenschmeigen....
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