How many different license plates can be made using 2 letters followed by 4 digits selected from the digits 0 through 9, if neither letters nor digits may be repeated?
To solve these kinds of problems, think of the license plate as 6 blanks you have to fill up _ _ _ _ _ _ and for each blank, ask yourself, "How many letters/numbers can I still put here?"
6 letters and 6 numbers
\[\frac{26 !}{(24)!} *\frac{10!}{(6)!} = 327,6000 \]
I think the answer is 68,250 there are 26 letters only i can use 2, i have 10 numbers only i can us 4 \[C(26,2)*C(10,4)\]
It's not \(\binom{26}{2}\) because BA1234 is different from AB1234.
so whats the answer? 6,760,000 3,276,000 1,965,600 68,250
It's 3276000 like what was said previously.
oh christ, did you even look at the anwser i posted , you just need to put the comma where it belongs. you know how to do that dont you ?
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