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\[(8\sqrt{18}\times3)\div16\sqrt{27}\] simplify showing full working...
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\[24\sqrt2\] \[\div\] \[16\sqrt3\] then reduce the 24 and 16 \[\sqrt 18\] = 9*2 so pull a 3 out and multiply 8*3... follow the same for \[16\sqrt27\]
One way to think about this is \[ \frac{3(8\sqrt{18})}{16\sqrt{27}} = \frac{3(8\sqrt{18})}{16\sqrt{9*3}} = \frac{3(8\sqrt{18})}{16*3\sqrt{3}} = \frac{8\sqrt{18}}{16\sqrt{3}} = \frac{\sqrt{18}}{2\sqrt{3}} = \sqrt{\frac{18}{12}} = \sqrt{\frac{3}{2}}\]
Thanks guys! :D
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