Solve for a. a+1/4=a+2/6+a+3/9=2 0 7 9 63
I would suggest pushing all the 'a' terms to the right and all the fractions to the left.
Although I must say that the second = sign does puzzle me a bit.
7
?
How does the second equal sign fit into the equation though, because a+1/4 is most likely not equal to 2.
7+1 divided by 4 is 2
Except that it would be 29/4 as it is not (7+1)/4
The way it is written they all equal 2, and you cannot add 1/4 to a and get 2, at the same time add 2/6, 3.9, AND 'a' and get 2. Could you verify that the original equation is accurate.
sorry i messed up its suppose to be 62 CoreyContini Solve for a. a+1/4-a+2/6+a+3/9=2
AH.. that makes a big difference. :)
ans is 7.as u can take variables one side &constant one side
Under the circumstances I'm not sure how you get any of the answers they list:\[a+\frac{1}{4}-a+\frac{2}{6}+a+\frac{3}{9}=2\rightarrow a+\frac{1}{4}+\frac{2}{6}+\frac{3}{9}=2\]\[a+\frac{1}{4}+\frac{2}{6}+\frac{3}{9}=2 \rightarrow a+\frac{9}{36}+\frac{12}{36}+\frac{12}{36}=2\]\[ a+\frac{9}{36}+\frac{12}{36}+\frac{12}{36}=2 \rightarrow a+\frac{33}{36}=2 \rightarrow a=2-\frac{33}{36}\]\[ a=2-\frac{33}{36} \rightarrow a=\frac{72}{36}-\frac{33}{36} \rightarrow a=\frac{39}{36} \rightarrow a=\frac{13}{12}\]
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