In the following figure, find the value of a. AB and CD are parallels.
Its kind of tricky for me. I tried for half an hour and I got anywhere. Any help will be welcomed
Do u know about angles in between parallel lines.
yeah i just read about that. I know the relationships
ABCD
Then try to make some eq. for {a}. U can do it dude.bcoz if i solve this it would be very long steps question.
i can give u only hints.
yeah but still dont get it
sorry
can you help me through skype. We can talk and is easier
first tell me what is the meaning of skype coz i don't know english very much .
skype is an application that allows voice over internet
How can i do that?
or msn?
only chating
online*
download skype in your computer and install it. Its eassy. I can wait for u
k!
Q+R+S = 180 Q = 180-11A R= 180-7A -8A S = 180-2A-4A
Im the meanwhile im going to try to solve another one
KABLAM!
That is exaclty where i get stucked smoothmath. What is the next step
Really? You got that far but could not solve it?
Plug in for Q,R, and S. Solve for a.
Q+R+S = 180 Q = 180-11A R= 180-7A -8A S = 180-2A-4A (180 -11A)+(180-7A-8A)+(180-2A-4A) = 180 Group like terms and blah blah blah.
Ok. let me do. correct me if im wrong. Im good at many other things, but geometry really got me. So, many of my questions are very easy for others :)
Don't be discouraged. This is a very tricky question. I am just quite good.
S = 180-2A-4A I'm not sure about this one
180-2A-4A would be the angle below S right?
So S should be 180-(180-2A-4A) = 180-180+2A+4A= 2A+4A
Not sure about this but I think it is worth a look.
Ah yes. Good catch, Zepp.
my net is not fast as i want .so sorry but if i have short solution for this I will post that later.
(180 -11A)+(180-7A-8A)+(2A+4A) = 180 is the corrected equation then.
:)
cool dont worry mashe.
Vertical angles are congruent, sum of interior angles of a quadrilateral is 360 and if two parallel lines are cut by a transversal, corresponding angles are congruent were used with arithmetic to get a = 7.5
so until now who has the correct answer?
Directrix?
Umm, @Directrix I would like you to explain why there's an angle with value 13a?
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