Question

Part 1 [3 points]: Find the solution to the equation 64(3 – x) = 42x.
Part 2 [4 points]: Use complete sentences to explain the method used to solve this equation.

This is my last question so I can finish this semester exam. Thank you if anyone helps! :)

Answer 1

by simplifying you get 192-106x=0
therefore, x = 96/53 or 1.81

Answer 2

can you elaborate more?

Answer 3

explain every step that you need to perform to solve this. so basically explain what you did in part 1..

Answer 4

64^(3 – x) = 4^(2x)

64 = 4^3

4^(3(3 – x)) = 4^2x
3(3 – x) = 2x
9 - 3x = 2x
9 = 5x
x = 9/5

I got this

Answer 5

*thumbs up*

Answer 6

oh then 9/5 is 1.8 gt it thanks

Answer 7

\[\LARGE 64(3-x)=42x \]
multiply 64 with both numbers into bracket. (with 3 and -x)
\[\LARGE 64\times 3+64\times (-x)=42x \]
now multiply ...
\[\LARGE 192 -64x=42x \]
now move -64x to the right side... (and its sign will change into +)
\[\LARGE 192 =42x+64x \]
now sum 42x and 64x
\[\LARGE 192 =106x \]
now divide both sides by 106
\[\LARGE \frac{192}{106} =\frac{106x}{106 } \]

\[\LARGE 1.81 =x \]

Answer 8

Kreshnik thank you so much! Helped a lot :D