Question

3sinx = 2cos^2x

solve.

Answer 1

\[3\sin x=2(1-\sin ^2x)\]
\[2\sin ^2x+3\sin x-2=0\]
\[(2\sin x-1)(\sin x+2)=0\]
You can finish it now.

Answer 2

Thank you, i got up to the step before the answer you gave me...

Answer 3

yw

Answer 4

So what did you get for x?

Answer 5

are there 2 answers for x?

Answer 6

Sin x = 1/2

Answer 7

cause it is also [0,2pi)

Answer 8

If sinx = 1/2, then x = pi/6 and 5pi/6

Answer 9

ok, thanks

Answer 10

yw