Ask
your own question, for FREE!
Mathematics
9 Online
OpenStudy (anonymous):
What are the square roots of 256?
a 13 and –13
b 15 and –15
c 16 and –16
d 128 and –128
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
use calculator
OpenStudy (anonymous):
i did i only get 1 answer!
OpenStudy (pigrenex):
C
OpenStudy (anonymous):
calculator wont give the answer holding negative sign
OpenStudy (anonymous):
@pigrenex how do you get that?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
a negative squared will always be positive
OpenStudy (maheshmeghwal9):
But in real maths there are 2 answers +16 & -16 since when both squared , we get 256
jimthompson5910 (jim_thompson5910):
Notice how 16*16 = 256 and (-16)*(-16) = 256
So this points us to the answer of C
OpenStudy (maheshmeghwal9):
hence , C
OpenStudy (anonymous):
but whenever you will try to find out the squareroots of a number you will get two..
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pigrenex):
-16 x -16 = 256
every time you multiply equal signs, you get a positive answer
OpenStudy (maheshmeghwal9):
(+)*(+)=(+) & (-)*(-)=(+)
OpenStudy (anonymous):
ok i got it thanks every one :)
OpenStudy (lgbasallote):
a fun way to solve
\(x^2 = 256\)
\(x^2 - 256 = 0\)
\((x+16)(x-16) = 0\)
\(x = 16; x = -16\)
OpenStudy (maheshmeghwal9):
wc:)
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!