Question

solve the system algebraically
y=x^3-x^2
y=-2x^2

Answer 1

Have you put y = - 2x^2 in the first equation and then tried to solve ?? If no, try it now :)

Answer 2

all i can get to is -2x^2=x^3-x^2

Answer 3

You should add 2x^2 on both sides

Answer 4

Yes and after @freckles said, take x^2 common out

Answer 5

x^2+x^3?

Answer 6

Yes, then take x^2 common out

Answer 7

then its just x???

Answer 8

It becomes
x^2(1+x) = 0

Then x^2 = 0 or 1+x = 0

Now you can take it from here hopefully :)

Answer 9

x= -1
y= -2?