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How would you sketch a graph with the y-intercept being -3, the x-intercept being 1 and -3, and i think the vertex is1.
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it cannot be plotted...considering as your vertex isnt even a coordinate lol
how would you find the vertex?
uhmm idk..you just gave it lol
i thought that was it im not sure - the problem is y=x^2+2x-3 so I am not sure
hmm i am assuming this is a parabola...
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yes
ahhh...hint..rewrtie it in the form \(y = a(x+h)^2 + k\) where \((h, k) = \text{vertex}\)
ok
|dw:1336376122598:dw| the vertex is (-1,-4) the graph is y+4=(x+1)^2
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