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what is the quadratic formula how do you use it to solve x2 + 6x = –3.
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is that x^2+6x=-3?
\[ax^2+bx+c=0\] is the general form you need in order to use the quadratic formula
yes it is
How do you use the quadratic formula
once you have it in that form, you use:\[x={-b \pm \sqrt{b^2-4ac} \over {2a}}\]
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That is the quadratic formula. Just substitute the values for a, b, and c
Just remember that the function MUST equal 0
Is it -6 -6 over /2
so you have to move the -3 to the other side so that you have x^2 +6x+3=0
You have two answers, the \[\pm\] so -6\[\pm\] sqrt(36-4(1)(3)) all divided by 2
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-3+- 6
\[x={{-6\pm \sqrt{36-4(1)(3)}}\over {2(1)}}\]
Do you know how to simplify that?
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