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find the roots of 2x^2-5x+1=0
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2.28 n 0.22 :P
the roots of the equation ax^2 + bx +c =0 is \[(-b \pm \sqrt{b ^{2}-4ac})/2a\] solve then
i plug in the values for a b c in the lower equation correct
\[-(-5)\pm \sqrt{-5^2-4(2)(1)\div2(2)}\] like that
−52−4(2)(1) only
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then divide your answer with 2(2)
\[5\pm \sqrt{25-8}\div4\]
yes
\[5\pm \sqrt{18\div4}\]
Nope 4 is not with 18
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now im confused on what to do next
Forget 4 and write ur answer
|dw:1336411742210:dw| not 18
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