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Mathematics 16 Online
OpenStudy (anonymous):

How do I know which trigger to use for this diagram?(adding the picture in a second)

OpenStudy (anonymous):

OpenStudy (anonymous):

No long explanations yet please. Just tell me Sin, Cos, or Tan first.

OpenStudy (anonymous):

to figure the height of the triangle

OpenStudy (anonymous):

tan65 needs to be utilized

OpenStudy (anonymous):

tell me the ratio according to the triangle...

OpenStudy (anonymous):

Thats what I thought. If i calculate the rest of the problem can you just tell me if i'm correct?

OpenStudy (anonymous):

sure...

OpenStudy (anonymous):

145 tan 65deg right?

OpenStudy (anonymous):

145 / tan 65deg

OpenStudy (anonymous):

Okay, now how did you figure it was Tan instead of Sin and Cos? Did you assume it was Tan because the degree was bordering the adjacent and hypotenuse?

OpenStudy (anonymous):

the angle given involved the opposite side given (145) and the height (unknown, x) so tan65 = 145/x... solving this ratio for x you have: x = 145/tan65

OpenStudy (anonymous):

the unknown height is the adjacent side to 65degrees..

OpenStudy (anonymous):

So lets say we didn;t know the width of the triangle, knew the height (as 145 lets say), and the 65deg angle was on the other-side of the triangle. How would we solve it then? I can draw it if you need me too.

OpenStudy (anonymous):

plz do...

OpenStudy (anonymous):

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