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(2xy^3)^4 - (3x^2y^6)^2
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and you're asking....?
Simplify.
uhmm distribute the exponent to every number i.e. (2^4)(x^4)(y^3)^4 simplify that...then do the same for the second term
(y^3)^4 becomes y^12, right?
yep
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\[(2x y{}^{\wedge}3){}^{\wedge}4-(3x{}^{\wedge}2y{}^{\wedge}6){}^{\wedge}2 \]Expand each side of the minus sign.\[16 x^4 y^{12}-9 x^4 y^{12} \]16 eggs minus 9 eggs is 7 eggs.\[7 x^4 y^{12} \]
OK, thanks!
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