Question

http://www.flickr.com/photos/65820711@N04/7155999664/

I GOT 520 MAKING SURE THANKS


If the length of AB = 64 cm and the length of BC = 8 cm, what is the length of CD? (Note that AB is tangent to circle F.)

Answer 1

Here's the theorem needed to solve the problem:

If a secant segment and tangent segment are drawn to a circle from the same external point, the product of the length of the secant segment and its external part equals the square of the length of the tangent segment.

Answer 2

OKAY THANK YOU DIRECTRIX

Answer 3

What equation did you use to get 520?

Answer 4

AB2 =BC × (BC + CD)
(64 cm)2 = 8 cm × (8 cm + CD)
4,096 cm =64 cm2 + 8 cm(CD)
4,032 cm2= 8 cm(CD)
504 cm = CD
i believe i miscalculated

Answer 5

Here's my work. Let's see.

(AB) ^2 = (BD)*(BC)
64 ^2 = 8 * (CD + 8)
4096 = 8 CD + 64
4032 = 8 CD
504 = CD

Answer 6

You wrote 520 up top. Your posted work looks correct to me.

Answer 7

504 is correct i had pout 520