Equilateral triangle has sides: 3x-3; 5x-2y; 6y-4. Find values of x and y. I keep getting crazy answers when I substitute back!

Question

Equilateral triangle has sides: 3x-3; 5x-2y; 6y-4.  Find values of x and y.  I keep getting crazy answers when I substitute back!

anonymous · Answer

3x-3=5x-2y=6y-4

anonymous · Answer

5 x - 2 y = 6 y - 4
Solve the above in terms of y, you will
get
$$
y=\frac{1}{8} (5 x+4
$$
replace y  in
3x-3=5x-2y
and solve for x.
Let me know what you find for x and then for y

anonymous · Answer

$$y=\frac{1}{8} (5 x+4)
$$
in my  post above

mertsj · Answer

I got x = -8/3 and y = -7/6   What did you get?

anonymous · Answer

That is what I got.

mertsj · Answer

I guess the asker is no longer interested.

anonymous · Answer

Hi you all... sorry was busy elsewhere.  i want to figure out again now that i know your answers.Thks for help.  will come in again later!!

anonymous · Answer

Hum, negative side......

anonymous · Answer

fter lots of stupid mistakes, I finally got the same.  Now I must check if the lengths of the sides of the triangle all make sense.  Thanks!