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derivative of 4cos[5pi(x)] sorry for my terrible syntax..
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\[-4\sin(5\pi x)\times 5\pi=-20\pi\sin(5\pi x)\]
but how i got lost in my u-sub
you integrating or differentiating?
diff right? then by the chain rule \[\frac{d}{dx}[cos(ax)]=-\sin(ax)\times a=-a\sin(ax)\]
oh okay.. wolframalpha was confusing me thank you
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you can write \(u=5\pi x, u'=5\pi\) if you like but it is a waste of time, you should do it in your head derivative of the outside function evaluated at the inside function time the derivative of the inside function
okay thanks
yw
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