Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

Add a constant term to the expression to make it a perfect square: x^2-((8ax)/9)

OpenStudy (anonymous):

what is (x+a)^2

OpenStudy (anonymous):

x^2 + 2ax +a^2

OpenStudy (anonymous):

we have x^2 and 2ax terms just figure out a^2

OpenStudy (anonymous):

hint: a is there in 2ax term!!

OpenStudy (anonymous):

i think that for (x+a)^2 the a value should be 4a/9? Hence the value for a^2 is 16a/81?

OpenStudy (anonymous):

yes here the value of a is -4a/9 which doesnt alter the value of a^2 cheer up you got the constant term you wanted

OpenStudy (anonymous):

so i'm right? :D

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Thank you!

OpenStudy (anonymous):

dont mention it

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!