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Add a constant term to the expression to make it a perfect square: x^2-((8ax)/9)
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what is (x+a)^2
x^2 + 2ax +a^2
we have x^2 and 2ax terms just figure out a^2
hint: a is there in 2ax term!!
i think that for (x+a)^2 the a value should be 4a/9? Hence the value for a^2 is 16a/81?
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yes here the value of a is -4a/9 which doesnt alter the value of a^2 cheer up you got the constant term you wanted
so i'm right? :D
yes
Thank you!
dont mention it
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