Part 1: Suppose you divide a polynomial by a binomial. How do you know if the binomial is a factor of the polynomial? Create a sample problem that has a binomial which IS a factor of the polynomial being divided, and another problem that has a binomial which is NOT a factor of the polynomial being divided.

Part 2: View and comment on the work of at least two other students. Try to choose students whose examples are different from the ones you created.

Question

Part 1: Suppose you divide a polynomial by a binomial. How do you know if the binomial is a factor of the polynomial? Create a sample problem that has a binomial which IS a factor of the polynomial being divided, and another problem that has a binomial which is NOT a factor of the polynomial being divided. 

Part 2: View and comment on the work of at least two other students. Try to choose students whose examples are different from the ones you created.

anonymous · Answer

first one 
Create a sample problem that has a binomial which IS a factor of the polynomial being divided,

start with your polynomial in factored for, make up anything where one is a "binomial" say 
(x2+2x+1)(x−4)
 multiply out, and then you will be sure that x−4 is a factor of your result  

for the second one,  you can take your answer for the first one and add some number to it.  then you can be sure that x−4 is not a factor

anonymous · Answer

so what would that look like
"?

anonymous · Answer

i have not much idea about binomials and polynomials i ask this from a friend 
so i dont have much idea how to actually make them

anonymous · Answer

http://www.myalgebra.com/algebra_solver.aspx try this it will help

anonymous · Answer

i m really really sorry sis that i cant help much

accessdenied · Answer

Do you know how to tell if a number like 13 is a factor of a number?  Basically ,if you have a number with a factor of 13 (like 26, 2*13, 13 is a factor), then we should be able to divide that number by 13 and get no remainder.
  26 / 13 = 2, 13 is a factor.
  28 / 13 = 2 R: 2, with good reason since 28 = 2*2*2*3. no 13's there.

anonymous · Answer

what?

accessdenied · Answer

It's the same concept with polynomials: if we divide off a binomial from a polynomial and get no remainder, then the binomial would be a factor of that polynomial.

anonymous · Answer

so how would i answer this to make since to my teacher?

accessdenied · Answer

I could try my best to explain whatever you're unsure of.  I'm just wondering what aspect of polynomials is confusing to you?

Sorry, I don't want to just give you an answer, it doesn't really help you understand it.  :(

anonymous · Answer

no like how am i suppose to answer this like am i suppose to give an example or explane? and if an example what should i write?