Question

Solve 2x2 + 3x + 5 = 0 I'm having troubles with this problem

Answer 1

what is 2*2?

Answer 2

4

Answer 3

or wait is that 2x^2?

Answer 4

2x^2

Answer 5

okay so in order to solve this you have to factor so normally the first thing you would try is to see if anything multiplies to make 5 and adds to make 3 so what are the factors of 5?

Answer 6

5 is prime, so 1, 5? right?

Answer 7

right plus you have a 2x so you might still be able to solve with factoring so the next thing I would do is go (2x )(x ) and then I would try filling in the blanks with different options and then doing foil until I found the right position for 1 and 5 and the right signs there is only four things to try

Answer 8

it would only be factorable if you had a negative.

Answer 9

If that doesn't work then you use the quadratic formula

Answer 10

x ≈ −4.28 and x ≈ 1.28?

Answer 11

then you could multiply the 2x by negative one and add it to x time 5 to get a positive 3x in the middle.

Answer 12

So 'x ≈ −4.28 and x ≈ 1.28' is correct?

Answer 13

This has no real solution are you working with imaginary numbers yet?

Answer 14

I thought so, but my friend told me it was " x ≈ −4.28 and x ≈ 1.28"

Answer 15

95 out of 100, high five guys. (y)!

Answer 16

maybe they just ignored to the took away the negative under the squareroot. Here I will give you a tip if you don't want to do the whole quadratic formula then you just do this if (b^2+4ac) is negative the the problem has no real solution do you know what is b and a and c ? you just set the equatio like this ax^2+bx+c so the c is always the number without a variable the "a" is the one with the exponent variable next to it and the b is the other one know what I mean? and yes high fives lol