Question

solve and show work!
(1/6b^2) + (1/6b) = (1/b^2)

Answer 1

(1/6b^2) + (1/6b) = (1/b^2)
multiply both sides of the equation by 1/b to get
(1/6b) + (1/6) = (1/b)
then subtract both sides by (1/b) to get
(1/6b) + (1/6)-(1/b) = 0
then subtract both sides by (1/6) to get
(1/6b) - (1/b) = -(1/6)
now solve the simplify the left side to one fraction (basically subtract the fractions) to get
(-5b/6b^2) = -(1/6)
this simplifies to
(-5/6b) = -(1/6)
multiply both sides by 6b to get
-5 = -b
so 5 = b is your solution
plug it in and you get 1/(6*25) + 1/(30) = 1/ 25 ----> 1/25 = 1/25