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Mathematics 21 Online
OpenStudy (anonymous):

A bag contains 6 cherry, 3 orange, and 2 lemon candies. You reach in and take 3 pieces of candy at random. The probability that you have 1 cherry candy and 2 lemon candies is

OpenStudy (anonymous):

nothing!;) haha jk jk i dont know :o

OpenStudy (anonymous):

1 cherry out of everything, is 1/11 2 lemons, 2/11 if you have AND,you multiply the two probabilities: so 2/11 * 1/11 = total probability that you have 1 cherry candy and 2 lemon candies = 2/11

OpenStudy (anonymous):

did i do it correct? lol i am not sure, check with raphael now

OpenStudy (anonymous):

(c1,l2,l3)U(l1,l2,C3)U(l1,C2,l3)

OpenStudy (anonymous):

|dw:1336532094323:dw|

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