Question

Write standard form of equation of a circle with radius r and center h,k)
R=square root of 3; (-4,3)

Answer 1

The center of (x-h)^2 + (y-k)^2 = r^2 is (h,k). In this case, the center is (-4,3). So h = -4 and k = 3. The number r is the radius. Since the radius is sqrt(3), we know that r = sqrt(3)


(x-h)^2 + (y-k)^2 = r^2


(x-(-4))^2 + (y-3)^2 = (sqrt(3))^2


(x+4)^2 + (y-3)^2 = 3


So the equation of the circle is (x+4)^2 + (y-3)^2 = 3

Answer 2

use the formula (x-h)^2 + (y-3)^2 = r^2