You have a CD with 15 songs, and you want to play 3 of them for your friends. How many different arrangements of 3 songs are possible? (Count two arrangements as different if they have the same 3 songs in a different order.)
A)455
B)45
C)2,730
D)3,375

Question

You have a CD with 15 songs, and you want to play 3 of them for your friends. How many different arrangements of 3 songs are possible? (Count two arrangements as different if they have the same 3 songs in a different order.)
A)455
B)45
C)2,730
D)3,375

cwrw238 · Answer

i think this is 15!/3!

anonymous · Answer

15 songs for the first, 14 for the the second 13 for the last (of the three) = 15*14*13 = 2,730

cwrw238 · Answer

yup - my stats aint brilliant!
micha is right

cwrw238 · Answer

if the order of the three choices didnt matter it would be 2730/6 = 455

anonymous · Answer

thank you!