PLEASE HELP!!! As well as finding the answer, could you explain how you'd solve this problem? Thanks! :)

Michaela climbed up a mountain at an average speed of 3 mi/h. She climbed down at an average speed of 5 mi/h. What is Michaela’s average speed for the entire trip? Round to the nearest tenth.

Question

PLEASE HELP!!!   As well as finding the answer, could you explain how you'd solve this problem?  Thanks! :)

Michaela climbed up a mountain at an average speed of 3 mi/h. She climbed down at an average speed of 5 mi/h. What is Michaela’s average speed for the entire trip? Round to the nearest tenth.

anonymous · Answer

assuming that the distance up the mountain = the distance down the mountain, she covered 1/2 of the total distance at 3 mi/h and 1/2 of the total distance at 5 mi/h.
Her average speed = 1/2 (3 mi/h + 5 mi/h) = 4 mi/h

anonymous · Answer

Suppose the mountain is 1 mile from bottom to top. So the trip up took 1/3 of an hour and the trip down took 1/5 of an hour. Average speed = total distance / total time = 2 mi / ( 1/3 h + 1/5 h ) = 3.75 mi /h.

anonymous · Answer

so the answer is 3.8