I really need help with finding the roots of graphs!!! PLEASE HELP ME :)

Question

savvy · Answer

yeah..!!! go on...

anonymous · Answer

well on the problem it shows a graph and it says Which of the following x-values are roots of the polynomials.Then it has the option to choose more than one answer and they are x=-4, x=0, x=-5, x=-, or x=2

savvy · Answer

ok..!!! $$y = a _{1} x^{n} + a _{2}x ^{n-1} + a _{3}x ^{n-2}..........................a _{n}x + a _{n+1}$$
the RHS is a polynomial of nth degree(the highest power of x)......
let it be equal to some y...
so here we put in some values of x to get some value of Y....hence x is an INDEPENDENT VARIABLE....
and Y is a DEPENDENT VARIABLE since it depends on what value does x take....
so ROOTS of a polynomial are those values of INDEPENDENT VARIABLE for which the DEPENDENT VARIABLE becomes ZERO...

savvy · Answer

|dw:1336597782783:dw|
the graph shows an arbitary curve....in this graph the at the circled points the graph intersects the x-axis which means at those points y=0....and hence those values o x for which the curve intersects the x-axis are the roots...

savvy · Answer

GOT IT...???? :)

anonymous · Answer

im not a hundred percent sure but i'll give it a try!! THANK-YOU!!! :D

savvy · Answer

you are welcome....give it a try and if u still got smthing...am here...

anonymous · Answer

|dw:1336598368672:dw| 
that is what the graph looks like that i am on