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Jocelyn has a jar of 54 coins consisting of dimes and quarters. If she has a total of $9.60, how many dimes does she have?
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\[25x+10y=960\]\[x+y=54\] would be one way to solve
put \(x\) as the number of quarters, then since the total number of coins is 54 the number of dimes you have is \(54-x\) then \[25x+10(54-x)=960\] solve for \(x\)
you got it from there?
ummok let me solve it
I got 284.8
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is it 28 coins?
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