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y = 2x^2 + 3x - 1 What values make y = 0?
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(there are 2)
Oh? OK, I'll keep that in mind, thanks.
Did you type in the equation correctly?
Yes, I did.
When I graph it, x has fractional values.
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Then I guess the answers are fractions.
I guess that makes sense, this equation does not seem factorable...
Use the quadratic formula. \[(-3\pm \sqrt 17)/4\]
OK, so is that the value you got for x? Also, inkyvoyd said there were 2 answers... Hmm...
Yes -- there is a plus and a minus answer to the answer above.
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Oh yeah, almost forgot about that. XD Thanks for your help.
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