Question

what are the restrictions for secx-sinxtanx=cosx ?

Answer 1

There will be a restriction when some angle makes me divide by 0.
Sin = 0/H. Since the hypotenuse for a right triangle is always positive, this has no restrictions.
Cos = A/H. Same situation.
Tan = 0/A What angles make the adjacent side 0? These angles will be restricted.
Sec = H/A This gives the same restrictions as the last.

If you need help picturing it, here's the unit circle.

Answer 2

I dont understand how smooth math explained it

Answer 3

Yo, gurl. What's tan(pi/2)?

Answer 4

doesnt work?

Answer 5

Soright.

Answer 6

so thats just the answer .. tan cannot equal pi/2

Answer 7

Any idea why? Maybe you can think of a situation where you'd want to take tangent of that angle?

Answer 8

i dont think im following you :\

Answer 9

Why is there no answer for tan(pi/2)?

Answer 10

asymptote at pi/2 ?