Question

for a projectile launched upwards from level ground if the speed of a projectile at the maximum height is half the speed of projection u its horizontal range is

Answer 1

clue v0x=v0/2

Answer 2

at the maximum height, the vertical component of velocity becomes zero. so only the horizontal component (u costheta) is present. from the given info. ,
\[u \cos \theta = u/2\]
\[\cos \theta = 1/2\]
\[\theta = 60\]

Answer 3

solve it on your own from here. and i'd rather suggest that you go through the theory part of the chapter before starting with the numerical problems

Answer 4

Write your solution here if it is not correct, we will help you.

Answer 5

i got it thanxxx guys