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Mathematics 19 Online
OpenStudy (anonymous):

geometry help ????

OpenStudy (anonymous):

.Triangle ABC has side lengths 3, 4, and 5. Do the side lengths form a Pythagorean triple? Explain.

OpenStudy (kymber):

a² + b² = c² Plug in numbers, if it's true then it's true.

OpenStudy (anonymous):

so its A then A. No, they do not form a Pythagorean triple; although 3squared + 4squared = 5squared , the side lengths do not meet the other requirements of a Pythagorean triple.

OpenStudy (kymber):

Other requirements? o_O I thought it was just that they had to equal...

OpenStudy (anonymous):

tally put up all the multiple choice answers.

OpenStudy (anonymous):

here are the rest of my choices its multiple choice :( B. No, they do not form a Pythagorean triple;3 suared + 4squared doesnt equal 5 squared . C. Yes, they form a Pythagorean triple; 3 squared +4squared=5 squared and 3, 4, and 5 are all nonzero whole numbers. D. Yes; they can form a right triangle, so they form a Pythagorean triple

OpenStudy (anonymous):

k hold on one sec k let me read it all at once

OpenStudy (anonymous):

kk

OpenStudy (kymber):

They are a Pythagorean triple because 3² + 4² = 5².

OpenStudy (anonymous):

oh mann :/ so D then?

OpenStudy (kymber):

No! It's not a Pythagorean triple JUST because it's a right triangle!

OpenStudy (anonymous):

tally kymber's equation is correct so tha answer should be D. n if im wrong im sorry bt to me its D.

OpenStudy (anonymous):

yay thats what i thought :) thank yall so much! that was bugging me.

OpenStudy (anonymous):

lol yur welcome.

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