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Mathematics 14 Online
OpenStudy (anonymous):

Look at the right triangle ABC. A student made the following chart to prove that AB2 + BC2 = AC2. What is the flaw in the student’s proof? Justification 3 should be “Angle ABC = Angle BAD and Angle BAC = Angle ABD”. Justification 4 should be “AB ÷ AD = AB ÷ AC because triangle ABC is similar to triangle ABD”. Justification 2 should be “BC ÷ DC = AC ÷ BC because triangle ABC is similar to triangle BDC”. Justification 1 should be “Angle ABC = Angle BCD and Angle BCA = Angle DBC”.

OpenStudy (anonymous):

OpenStudy (anonymous):

i dont get it

OpenStudy (precal):

is this the problem?

OpenStudy (anonymous):

yes

OpenStudy (callisto):

The second one is wrong... It should be BC AC --- = --- DC BC

OpenStudy (callisto):

(corr. sides, ~△s)

OpenStudy (anonymous):

thank yoou!

OpenStudy (callisto):

welcome

OpenStudy (anonymous):

CORRECTION!!! the answer is C Justification 2 should be "BC ÷ DC = AC ÷ BC because triangle ABC is similar to triangle BDC."

OpenStudy (callisto):

@taylittle321, can you explain your answer?

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