What is the equation of the line passing through (–6, 1) and perpendicular to the line y = –3x + 1 in slope-intercept form? y = 3x + 4 y = x + 3 y = –3x – 6 y = x – 5
No clue, like I feel sooo dumb with this math stuff. I had a baby and just started back my schooling, I have been out of school for about half a year now...... :'(
okay so what you do is do the rise/ run so basically it's givien 2 ya
y=mx+b and M=slope so like the equation given 2 you y=-3x+1 so tell me what is the slope?
do you still need my help?
Well,, I passed Algebra 1 with a 98 A. Now that I'm on this it's hrd to me since I had a baby and was out of school for a while, I forgot a lot of what I learned before I had the baby.
Izzy25. yes please.
can you answer this question then? y=mx+b and M=slope so like the equation given 2 you y=-3x+1 so tell me what is the slope?
idk? :'(
-3 darling, -3.....i just hope when i explain to you you will understand?
oh...... m=slope!!!!!!!!!!!!
I didn't read that part! SORRY!
it's fine i do it all the time . okay so since the slope is -3 we do something that is called the Negative reciprocal because the key word is PERPENDICULAR, so your slope should be 3
Okay I'm following you far.
so now you got that you just rewrite the equation... instead like this though y=3x+b because why? because we have no idea what b is for the perpedicular like and then you plug in the coordinates given to you the coordinates (-6,1) that is
* line
y=-3x-6
is that ur answer?
Yeah,
okay then... so you get it?
YES! I got it right THANKS
metal please then :D
There you go girl! :D
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