Question

How do I prove the identity: 1/sinx - sinx = cosx/tanx?

Answer 1

\[\frac{1-\sin x(\sin x)}{\sin x}\]\[\frac{1 - \sin^2x }{\sin x}\]\[\frac{\cos^2x}{\sin x}\]

Answer 2

= 1 - sin^2 x
----------- yea saifoo got it
sin x

Answer 3

\[\frac{\cos x * \cos x}{\sin x} \to \cos x* \frac{\cos x}{\sin x} \to \cos x (\frac{1}{\tan}) \]

Answer 4

wait why is did you multiply sinx again? ahh D:

Answer 5

Where?

Answer 6

1- sinx*sinx

Answer 7

I took LCM as sinx

Answer 8

the lowest common multiple?

Answer 9

Yes sir.

Answer 10

okay thanks!