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There are 6 red apples, 4 yellow apples, and 2 green apples in a bucket. Maria will chose two apples at random without replacement. What is the probability that Maria will choose a red apple and a green apple?
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thank you but unfourtanettly that is not one of the answer choices
1/11 ?
yea thats one
\[ \huge \frac {\binom 6 1 \times \binom 2 1}{12\times 11} = \frac 1 {11} \] I should have read the question carefully.
thank you so very much
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