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Mathematics 19 Online
OpenStudy (anonymous):

Factor!!! x^2+11x+24

OpenStudy (lgbasallote):

Hint: break down the middle term into 8x + 3x can you solve it then?

OpenStudy (anonymous):

No, I do not know how to do this

OpenStudy (lgbasallote):

what i meant was rewrite it as \(x^2 + 8x + 3x + 24\) that's equal to the original expression right?

OpenStudy (anonymous):

Correct

OpenStudy (lgbasallote):

now group it \((x^2 + 8x) + (3x + 24)\) now what's common in the first group?

OpenStudy (anonymous):

8??

OpenStudy (pradius):

X?

OpenStudy (lgbasallote):

\(x^2 + 8x\) is the first group...do you see an 8 in the first term? "common factor" means something bot x^2 and 8x has

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