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this seems tricky =_= Prove: \[\frac{2 \tan x}{1 + \tan^2 x} = \sin (2x)\]
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i tried changing 1 + tan^2x to sec^2 x but it did nothing :/
change tanx to sinx/cosx and try
i dont see it o.O
\[\frac{\frac{2\sin x}{\cos x}}{1 + \frac{\sin^2 x}{\cos^2 x}}\]
Clear the compound fraction action! :)
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lol didnt recognize you :p why change? haha and compound frawhat?
srsly...i thought a new mod was in town
Multiply top and bottom by cos^2(x)
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