Question

x^2+6x? need help don't give straight answers plz

Answer 1

x^2+6x=0
you mean this?

Answer 2

yes i'm a little slow at math.

Answer 3

factor x out first

Answer 4

See, take the common factor i.e. x and put that outside the bracket.

Answer 5

\(\Large \color{purple}{\rightarrow x(? + ?) }\)

Answer 6

x(x+6)=0
and now look which values of x will mach this

Answer 7

Yes, now, either x = 0 or x + 6 = 0

x + 6 = 0
x = -6

So, we can infer that x = 0 or -6

Answer 8

thanks to both of you :)

Answer 9

No problem, Amanda. We need keen askers like you on this site :)

Answer 10

x(x+6)=0
either x = 0
or x+6=0 --> x=-6

Answer 11

so the answer would be x(x+6) right?

Answer 12

there are two possible answers
x={0,-6}

Answer 13

thats the only one i have that makes since haha..

Answer 14

x^2+6x = 0
first factor it

Answer 15

If you have around two hours of time, and want to learn completnig the square, go ahead and try to read http://openstudy.com/users/inkyvoyd#/updates/4fab0d4ee4b059b524f6d7b1

Answer 16

i just need to know if x(x+6) could be an answer?

Answer 17

x(x+6) = 0
now lets find the two solutions to this
divide both sides by x
x(x+6) = 0
Notice that if x = 0 then both sides are zero thus it is one of the solutions
if x = - 6 then we have
-6(0) = 0
0 = 0
thus -6 is a solution for x

Answer 18

sorry if I ruined the question for you but I felt it would be better if I just explained the answers, besides you will see about a million of these problems in the future if you take math in uni or college

Answer 19

or if you are already in college or uni other math classes

Answer 20

i'm in high school and i'm learning college math already so yea lol i'm not good at this.

Answer 21

its not hard really just remember to factor and if all else fails use the quadratic formula

Answer 22

alright thanks alot.

Answer 23

Yes, it is x(x + 6)

Answer 24

https://www.youtube.com/watch?v=H5AM1bzqCQw

Answer 25

this video shows you how to solve the quadratic formula

Answer 26

You had to factor right? @amanda132