Question

What is the limit of e^-n as n approaches infinite?

Answer 1

zero..

Answer 2

How did you get the answer?

Answer 3

value of e is 2.71 approximately now if u put in the power of e a very large no to it..
e^-n=1/e^n

e^n approaches infinite hence e^-n which we can write it as 1/e^n approaches zero because you know if u divide 1 with a very large no. say infinite it approaches zero.. got it?

Answer 4

Thank you very much! I didn't think of rewriting it as denominator.