What's the simplified product of √t(8√2 - 7)?
When you multiply radical terms, you should be careful to only multiply the numbers outside of the radical together and the numbers inside the radicals together. So for 2√10k * 5k√2? It would be: 10k sqrt(20k) Then, you could simplify the radical further: 10k sqrt( 4*5k) 20k sqrt(5k) ^That is the simplified product!
Thank you! Could you help with √t (8√2 -7)
would I have to "distribute" the √t into the equation?
Yup! That's how you would start. Remember, you need to multiply the t by only the numbers/terms inside of the other radicals.
since there is no sqrt in the second term, you would just multiply it by sqrt1
\[8\sqrt{2t} -7\sqrt{t}\] ^That's what you should get.
thank you again!!!!
No worries lol ^_^
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