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y^2+2y=8
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potato . . . . . what are you asking?
Did you learn how to solve quadratic equations? Because it is a simple case of a quadratic equation. You have to apply the "quadratic formula" yo solve.
ditto ditto
it says to factor
subtract 8 from both sides first
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y^2+2y=8 -8 -8 8-y^2+2y (-4-y) (2-y) -8+4y-2y+y^2 -8+2y-y^2 original answer
does this look correct?
lol stop with (-4 0 y)(2-y) that's the factored form already
(-4 - y)(2-y)*
y^2+2y=8 y^2 + 2y -8 =0 (y+4)(y-2)=0 (y+4)=0 or (y-2)=0 Solve these 2 equation, can you?
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thats where im stuck..i was told to solve for y
Basic equation.... (y+4)=0 or (y-2)=0 y+4-4 = 0-4 or y-2+2 =0+2 What do you get?
thanks
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