a particle moves along x axis in such a way that its x-coordinates varies with time t according to the relation x-2- 5t +6t^2 the imitial velocity (at t=0) of the particle is?

Question

anonymous · Answer

do you mean  x=2- 5t +6t^2 instead of  x-2- 5t +6t^2

that minus, is it right?

or...?

anonymous · Answer

the ans=-5 units

anonymous · Answer

can u solve for  it

anonymous · Answer

well i think all have to be in terms of t 

BUt i'd take the  derivitive of x(t) then evaluate it at 0 x'(0)

anonymous · Answer

hmm if x is correct then i'd use implicit differentiation
x=x(t)-2- 5t +6t^2

anonymous · Answer

i think should be the relation x= 2-5t + 6t^2
v=dx/dt = -5 + 12t
so when t=0 v= -5

anonymous · Answer

thanzzzz

anonymous · Answer

yeah it is easy when x=2-5t...