Question

a particle moves along x axis in such a way that its x-coordinates varies with time t according to the relation x-2- 5t +6t^2 the imitial velocity (at t=0) of the particle is?

Answer 1

do you mean x=2- 5t +6t^2 instead of x-2- 5t +6t^2

that minus, is it right?

or...?

Answer 2

the ans=-5 units

Answer 3

can u solve for it

Answer 4

well i think all have to be in terms of t

BUt i'd take the derivitive of x(t) then evaluate it at 0 x'(0)

Answer 5

hmm if x is correct then i'd use implicit differentiation
x=x(t)-2- 5t +6t^2

Answer 6

i think should be the relation x= 2-5t + 6t^2
v=dx/dt = -5 + 12t
so when t=0 v= -5

Answer 7

thanzzzz

Answer 8

yeah it is easy when x=2-5t...