Mathematics
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OpenStudy (anonymous):
Find the product of (x − 3)2.
x2 + 6x + 9
x2 − 9
x2 − 6x + 9
x2 + 9
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OpenStudy (anonymous):
Same thing?
OpenStudy (anonymous):
x^2 - 9?
Parth (parthkohli):
\(\Large \color{Midnightblue}{\rightarrow (a - b)^2 = a^2 + b^2 - 2ab }\)
Parth (parthkohli):
Basically,
\(\Large \color{Midnightblue}{\rightarrow (a \pm b)^2 = a^2 + b^2 \pm 2ab }\)
OpenStudy (anonymous):
x^2 - 9 - 2x^3?
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OpenStudy (anonymous):
x^2 + 9 - 6?
Parth (parthkohli):
- 6x*
Parth (parthkohli):
\(x^2 + 9 - 6x\)
OpenStudy (anonymous):
Explain please...
OpenStudy (anonymous):
Why - 6x?
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Parth (parthkohli):
\(\Large \color{Midnightblue}{\rightarrow (x - 3)^2 = x^2 + 3^2 - 2(x * 3) }\)
\(\Large \color{Midnightblue}{\rightarrow (x - 3)^2 = x^2 + 3^2 - 6x }\)
OpenStudy (anonymous):
I see.
OpenStudy (anonymous):
But that's not one of my options..
OpenStudy (anonymous):
@ParthKohli That's not one of my options..
OpenStudy (anonymous):
@ParthKohli That's not one of my options..
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Parth (parthkohli):
Just simplify it.
OpenStudy (anonymous):
Umm... How?
Parth (parthkohli):
\(\Large \color{Midnightblue}{\rightarrow x^2 + 9 -6x }\)
Parth (parthkohli):
\(3^2 = 9\)
OpenStudy (anonymous):
None of them are my options either..
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Parth (parthkohli):
It's the third one!
OpenStudy (anonymous):
Try this using distributive property .
(x-3)(x-3)
x*x+(-3)(-3)+(-3)x+(-3x).
x^2+9-6x
Parth (parthkohli):
My answer was right, but it wasn't according to the degrees.