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Find the derivative
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quotient rule! ((denominator * derivative of numerator) - (numerator * derivative of denominator))/ (denominator^2)
I got (6)/(x-1)^2 is this correct?
Try to factor out first if you can.
@Romero , you are right, x-4 cancels in the numerator and denominator
Then apply the rule given by @Puzzhang
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\[\frac{x^2-5x+4}{x^2+x-20} =\frac{(x-4)(x-1)}{(x-4)(x+5)}\]
Cancel it out first then use quotient rule on \[\frac{(x-1)}{(x+5)}\]
so 6/(x+5)^2?
yep!
ok thanks!
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