Given a point P=(14,7) on a parabola of the form y=ax^2, find the equation of the parabola.

Question

kinggeorge · Answer

We're given a point $x=14, \;\; y=7$ and an equation $y=ax^2$. Simply plug in and evaluate for a.$$7=a\cdot(14^2)$$

anonymous · Answer

once i find a, how do i write the equation i got a=0.4

anonymous · Answer

*a=0.04

kinggeorge · Answer

It would be better to write $a$ in it's exact form as $$1 \over 28$$instead of approximating it as $0.04$ since we're looking for the particular equation of that form with that point. 

So now, all you need to do is substitute your value of $a$ into the original equation.

anonymous · Answer

oh okay thank you! i kept trying to put 0.04 and i wasn't working.

kinggeorge · Answer

You're welcome.