Question

Given a point P=(14,7) on a parabola of the form y=ax^2, find the equation of the parabola.

Answer 1

We're given a point \(x=14, \;\; y=7\) and an equation \(y=ax^2\). Simply plug in and evaluate for a.\[7=a\cdot(14^2)\]

Answer 2

once i find a, how do i write the equation i got a=0.4

Answer 3

*a=0.04

Answer 4

It would be better to write \(a\) in it's exact form as \[1 \over 28\]instead of approximating it as \(0.04\) since we're looking for the particular equation of that form with that point.

So now, all you need to do is substitute your value of \(a\) into the original equation.

Answer 5

oh okay thank you! i kept trying to put 0.04 and i wasn't working.

Answer 6

You're welcome.