Two forces F1 and F2 act on a 5.00 kg object. Taking F1=20.0N and F2=15.00N, find the acceleration of the object for the configurations:

a) mass m with F1 acting in the positive x direction and F2 acting perpendicular in the positive y direction

b) mass m with F1 acting in the positive x direction and F2 acting on the object at 60 degrees above the horizontal.

Question

Two forces F1 and F2 act on a 5.00 kg object. Taking F1=20.0N and F2=15.00N, find the acceleration of the object for the configurations:

a)	mass m with F1 acting in the positive x direction and F2 acting perpendicular in the positive y direction

b)	mass m with F1 acting in the positive x direction and F2 acting on the object at 60 degrees above the horizontal.

ujjwal · Answer

|dw:1337008080583:dw| this diagram is for (a) find the net force F using relation$$F=\sqrt{F _{1}^{2}+F _{2}^{2}+2F _{1}F _{2}\cos \theta}$$ where theta is angle between two forces.. in this situation theta is equal to 90 degrees... after you find net force F, using relation F=ma i.e a=F/m , you can find acceleration of object..
For (b) use the same relation given above to find the net force.. only the value of theta is different... and after you find net force, follow the same process as above to find acceleration..