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derivative of power function f(x) = 3/(x2−x−12)
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do i need to take the derivative or antiderivative or none
do you need to differentiate f ?
im trying to get the power series representation and then interval of convergence
i was able to get (-3*49)/4 * 1/(1-(2x-1)^2)
oh yeah its around the center x=1
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you expansion Taylor series ?
im trying to get this into geometric series form
about center x=1
I think x^2-x-12=(x-4)(x+3) 3/(x^2-x-12)=a/(x-4)+b/(x+3) with a=3/7, b=-3/7 \[3/7/(x-4)=3/7(1/(x-1)\sum_{n=0}^{\infty}[3/(x-1)]^{n}\]
with b/(x+3) similar
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WOW I figured out that i did wrong!! i didnt recognize that x^2-x-12 was the same as (x-4)(x+3) i know what to do now i have to do partial frac. then i can solve it
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