Ratios
The small rectangle had length of x and width of x + 3
The large rectangle had a length of 3x and a width of x^2 + 7x + 12
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OpenStudy (anonymous):
I know I'd end up having:
3(x^2 + 7x + 12) = 3x(x + 3)
OpenStudy (anonymous):
which would be:
3x^2 + 21x + 24 = 3x^2 + 9x
OpenStudy (anonymous):
is x^3 + 4x^2 + 3x but what is the simplified form?
OpenStudy (anonymous):
let me know if i did anything wrong in the steps
OpenStudy (anonymous):
HOW can i put it in simplified form?
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OpenStudy (mertsj):
\frac{\[\frac{3}{3x}=\frac{x+3}{(x+4)(x+3)}\]
OpenStudy (mertsj):
\[\frac{1}{x}=\frac{1}{x+4}\]
OpenStudy (mertsj):
\[x+4=x\]
OpenStudy (mertsj):
\[4=0\]
OpenStudy (mertsj):
No solution
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OpenStudy (anonymous):
But these are my options:
3(x + 4)
x + 3 /x^2 + 7x + 12
3x /x + 4
1 /3x + 4
OpenStudy (mertsj):
I don't think you posted the problem correctly because you ask what is the value of x in the proportion and then you list a bunch of answers that contain x.
OpenStudy (mertsj):
So either you have posted the wrong question or the wrong proportion.
OpenStudy (anonymous):
Oh Im so sorry!!! I posted the wrong question! Its the simplified proportion I think